Van Der Waals Equation

The pressure exerted by 1 mole of CO₂ at 273 K, is 34.98 atm. Assuming that volume occupied by CO₂ molecules is negligible, the value of van der Waals' constant for attraction of CO₂ gas is :

In Van der Waal’s equation of state for a non-ideal gas, the term that accounts for intermolecular forces is:

When deviation is more in the behaviour of a gas from the ideal gas equation PV = nRT ?

Calculate molecular diameter (in nanometer) for a gas if its molar excluded volume is $3.2\mathrm{\pi } \mathrm{ml}$. Give the answer by multiplying with $10.$

$($Take$\left.{\mathrm{N}}_{\mathrm{A}}=6.0\times {10}^{23} \right)$

Among the following, Van der Waals constant $\text{'}\mathrm{a}\text{'}$ would be maximum for _____

The van der Waals coefficient $\mathrm{a}$ (expressed in $\mathrm{atm}·{\mathrm{dm}}^6·{\mathrm{mol}}^{-2}$) for four different gases are: $\mathrm{He} 0.0341; {\mathrm{H}}_2 0.242; \mathrm{Kr} 5.125; {\mathrm{O}}_2 1.364.$ Based on the data given above, the gas that will be expected to have the lowest critical temperature ${\mathrm{T}}_{\mathrm{c}}:$

Which of the following expressions is correct between the van der Waals constant $\mathrm{b}$ and the radius $\mathrm{r}$ of spherical molecules?

The Van der Waal's equation for real gases is $\left(\mathrm{P}+\mathrm{a}{\left(\frac{\mathrm{n}}{\mathrm{V}}\right)}^2\right)\left(\mathrm{V}-\mathrm{nb}\right)=\mathrm{nRT}$

In the above equation, the terms a $(\mathrm{n}/\mathrm{V}{)}^2$ and $(-\mathrm{nb})$, respectively represents the corrections for:

For one mole of a van der Waals gas when $\mathrm{b}=0$ and $\mathrm{T}=300 \mathrm{K}$, the $\mathrm{PV} \mathrm{vs} \mathrm{I}/\mathrm{V}$ plot is shown below. The value of the van der Waals constant $\text{'}\mathrm{a}\text{'} (\mathrm{atm}. {\mathrm{litre}}^2 {\mathrm{mol}}^{-2})$is

The term that accounts for intermolecular force in van der Waals' equation for non ideal gas is :

$1$ mole of real gas $(\mathrm{a}=1.4)$ occupies a volume of $0.1$ $\mathrm{L}$ at $300$ $\mathrm{K}$, the pressure of gas will be:

The correction factor $\text{'}a\text{'}$ to the ideal gas equation corresponds to    

If $\mathrm{V}$ is the volume of one molecule of a gas, the van der waal's constant $\text{'}\mathrm{b}\text{'}$ is:

For a real gas under low pressure conditions, which of the following graph is correct?

In Van der Waal equation at constant temperature $300 \mathrm{K}, \mathrm{a}=1.4 \mathrm{atm} {\mathrm{lt}}^2 {\mathrm{mole}}^{-2}, \mathrm{v}=100 \mathrm{ml}, \mathrm{n}=1 \mathrm{mole},$ what is the pressure of gas:

In the Vander Waal's equation, $\text{'}\mathrm{a}\text{'}$ signifies:

For real gases, Van der Waals equation is written as.

$\left(\mathrm{p}+\frac{{\mathrm{an}}^2}{{\mathrm{V}}^2}\right)\left(\mathrm{V}-\mathrm{nb}\right)=\mathrm{nRT}$

where $\text{'}\mathrm{a}\text{'}$ and $\left(\mathrm{b}\right)$ are Van der Waals constants.

Two sets of gases are:

$\left(\mathrm{I}\right)$ ${\mathrm{O}}_2, {\mathrm{CO}}_2, {\mathrm{H}}_2$ and $\mathrm{He}$
$\left(\mathrm{II}\right)$ ${\mathrm{CH}}_4,{\mathrm{O}}_2$ and ${\mathrm{H}}_2$

The gases given in set-$\mathrm{I}$ in increasing order of $\text{'}\mathrm{b}\text{'}$ and gases given in set-$\mathrm{II}$ in decreasing order of $\text{'}\mathrm{a}\text{'}$, are arranged below. Select the correct order from the following:

At high temperature and low pressure van der Waal's equation can be expressed as

Vander Waal's constants 'a' and 'b' are related with....., respectively.

The term that corrects for the attractive forces present in a real gas in the Vander Waals equation is: